2X 3Y 9 In Slope Intercept Form

📈write the slope intercept form of the equation for the line.Y=2x1Y=1

2X 3Y 9 In Slope Intercept Form. In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3 Divide each term in by and.

📈write the slope intercept form of the equation for the line.Y=2x1Y=1
📈write the slope intercept form of the equation for the line.Y=2x1Y=1

Subtract 2x from both the sides of the equation 2x + 3y = 9. Select two x x values, and plug them into the equation to find the corresponding y y values. So we get our equation into this form: A straight line graph is of the form: Web to find the slope of a line, we find the rate at which the value of 'y' is increasing as we increase the value of 'x' by one unit. Subtract from both sides of the equation. Subtract from both sides of the equation. Rearrange the equation by subtracting what is to the. Divide each term in by and. (0,3) ( 0, 3) any line can be graphed using two points.

(a) parallel to the given line, and (b) perpendicular to it. So we get our equation into this form: Subtract 2x from both the sides of the equation 2x + 3y = 9. Y = 2 3x− 3. Divide each term in by and. A straight line graph is of the form: In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3 Web to find the slope of a line, we find the rate at which the value of 'y' is increasing as we increase the value of 'x' by one unit. Y = mx + c m is the gradient c is the intercept which is the point at x = 0 where the line cuts the y axis. Subtract from both sides of the equation. 2x +3y = 9 3y = −2x + 9 y = − 2 3 x +9 so the slope or gradient.